> It's a simple reason if you have the math background:
Those with an engineering background will point out that extended
frequency range generally comes at cost to some other metric. No
parameter comes for free; it's traded off against something else.
(You mention that of course, but I wanted to stress that it's just as
likely to be a net-loss tradeoff as a net-gain).
> A wide-band
It typically loses a _substantial_ amount of efficiency. The power
amplifier then has to work that much harder, and it will see objective
fidelity drop precipitously as power increases.
Nothing for free.
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