Re: [LAU] Where do the 60 degrees for stereo come from?

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To: Charles Henry <czhenry@...>
Cc: <linux-audio-user@...>
Date: Monday, June 20, 2011 - 10:33 pm

On Mon, Jun 20, 2011 at 04:41:46PM -0500, Charles Henry wrote:

No, this is wrong. The gradient is 90 degrees out of
phase w.r.t. pressure, and rises by 6 dB/oct w.r.t.
pressure.

The velocity vector is the time integral of the
gradient, and consequently it is in phase with
pressure, and the P/V ratio is independent of
frequency (assuming far field).

Ciao,

--
FA

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Messages in current thread:
Re: [LAU] Where do the 60 degrees for stereo come from?, Fons Adriaensen, (Thu Jun 16, 8:35 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Philipp Überbacher, (Fri Jun 17, 8:58 am)
Re: [LAU] Where do the 60 degrees for stereo come from?, Fons Adriaensen, (Fri Jun 17, 5:48 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Philipp Überbacher, (Fri Jun 24, 11:58 am)
Re: [LAU] Where do the 60 degrees for stereo come from?, Fons Adriaensen, (Fri Jun 24, 1:13 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Charles Henry, (Mon Jun 20, 9:41 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Fons Adriaensen, (Mon Jun 20, 10:33 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Philipp Überbacher, (Thu Jun 16, 8:56 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Julien Claassen, (Thu Jun 16, 8:21 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Philipp Überbacher, (Thu Jun 16, 8:41 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Karl Hammar, (Fri Jun 17, 12:45 pm)
Re: [LAU] Where do the 60 degrees for stereo come from?, Monty Montgomery, (Thu Jun 16, 8:43 pm)