Re: [linux-audio-user] various questions (long)

Previous message: [thread] [date] [author]
Next message: [thread] [date] [author]
To: Linux Audio User Mailing List <linux-audio-user@...>
Date: Tuesday, March 4, 2003 - 9:50 am

On Tue, Mar 04, 2003 at 02:57:48 -0600, Levi Burton wrote:

Yes, its easy

There are 4 beats in a bar (well, in 4/4 music)
so 60 seconds / 120 BPM means there is 1/2 second per beat
therefore there are 4 * 1/2 = 2 seconds per bar

in short: bar time = 240
---
bpm

I probably didn't explain that very well, but I expect someone will post a
better explanation.

Your triggered record thing sounds like a useful feature for TimeMachine
(http://plugin.org.uk/timemachine/) if I find time. It should be easy.

- Steve

Previous message: [thread] [date] [author]
Next message: [thread] [date] [author]

Messages in current thread:
[linux-audio-user] various questions (long), Levi Burton, (Tue Mar 4, 9:08 am)
Re: [linux-audio-user] various questions (long), janne halttunen, (Tue Mar 4, 6:22 pm)
Re: [linux-audio-user] various questions (long), Kai Vehmanen, (Tue Mar 4, 9:25 pm)
Re: [linux-audio-user] various questions (long), Steve Harris, (Tue Mar 4, 9:50 am)
Re: [linux-audio-user] various questions (long), Maarten de Boer, (Tue Mar 4, 9:48 am)
Re: [linux-audio-user] various questions (long), Tim Hall, (Tue Mar 4, 12:50 pm)
Re: [linux-audio-user] various questions (long), Guy Daniel CLOTILDE, (Sat Mar 8, 10:14 am)
Re: [linux-audio-user] various questions (long), luis jure, (Sat Mar 8, 10:40 am)
Re: [linux-audio-user] various questions (long), Richard Seymour, (Mon Mar 10, 4:41 pm)
Re: [linux-audio-user] various questions (long), Richard Seymour, (Mon Mar 10, 4:58 pm)
Re: [linux-audio-user] various questions (long), Guy Daniel CLOTILDE, (Sat Mar 8, 10:28 am)
Re: [linux-audio-user] various questions (long), Tim Hall, (Sat Mar 8, 2:29 pm)
Re: [linux-audio-user] various questions (long), Guy Daniel CLOTILDE, (Tue Mar 4, 11:26 am)