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falktx|work | Q: is 0 as valid minimum value for a logarithmic port? | 16:56 |
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ssj71 | mathematically no, that would be like -Inf | 17:06 |
ssj71 | but practically it could just allow the host to decide the cutoff | 17:07 |
rgareus | it isn't valid | 17:20 |
rgareus | log (0) is not -inf, it is undefined | 17:20 |
rgareus | if you approach it from above the limes is indeed -inf. | 17:21 |
rgareus | it's easy to see by inversion there is no value x for which a^x = 0 | 17:22 |
rgareus | in Ardour's case if the min/max range crosses zero or one of the value is zero, Ardour ignores the log-scale property. | 17:27 |
ssj71 | rgareus: right, but its the same problem as setting the "limit" of a port at negative infinity | 17:29 |
ssj71 | its asymptotic | 17:29 |
rgareus | does lv2 allow -inf as port value? | 17:31 |
* rgareus imagines an infitly long fader. | 17:31 | |
falktx|work | it's a valid float number.. | 17:31 |
rgareus | so is NaN | 17:31 |
ssj71 | so it makes sense that 0 is not valid in a logarithmic port. thats my point | 17:35 |
rgareus | yep. | 17:35 |
rgareus | just like it makes no sense to say 0 Hz. | 17:35 |
ssj71 | I use DC signals all the time | 17:36 |
rgareus | heh | 17:36 |
ssj71 | not for audio though | 17:36 |
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